soru

5x-7y+21z=4 
17x+12y-5z=5 ise 


2x+391y-832z=? 



cözüm


(5x-7y+21z=4)a 
(17x+12y-5z=5)b 
-------------------- 

5ax-7ay+21az=4a 
17bx+12by-5bz=5b 
+ 
------------------------- 
2x+391y-832z=5a+4b=? 

5ax+17bx=2x 
-7ay+12by=391y 
21az-5bz=-832z 
 
iki bilinmeyenli uc denklem cozuldugu zaman 
a=-37 b=11 cikar. 

sonuc : 
2x+391y-832z=5a+4b=(-37*5)+(4*11)=-141. 



Matematikciler.COM